Mass Spring Oscillations Lab
Objective: Find the relationship between period and spring constant as well as with the amount of mass that is oscillating.
Set up: There were a total of four groups each with a different spring, the appropriate mass so that way each group would have the same amount of oscillating mass determined by the equation (mosc= mhang+ mspring/3). We used a motion sensor and lab Pro to graph our results and place an appropriate fit.
Data Collection: The first step for our group to do is to find the spring mass of our given spring. To do so we weighed the spring for its mass, We then hung the spring to measure its length at a relaxed state, then once more with a .1 kg mass hanging at the end without oscillation:
Fnet= 0N= mg - kxstretch xstretch= x- xo = .067 m
m= 26 g
mg= k(x -xo) => k= mg k= 14.64 N/m
(x- xo)
We then went on to derive our equation for omega and, eventually, for our period using Newton's second Law as seen in (fig. 1).
![]() |
| Figure 1. All my derivations and notes from the set up as well as comparisons to our actual unfortunately there is a mistake in the percentage comparison on theoretical period to actual. |
We now had our theoretical equation for period of our set up and we tested with 4 trials for consistency. We counted the periods with in a 5 second trial and found that our theoretical calculation was almost 100% accurate to our actual. When we graphed our results compared to others and graphed them with an appropriate curve fit we find something interesting. First, how we analytically found the curve fit to be a power fit was this observation:
Our period came to a form of:
T= 2pi*(m/k)^.5
It seems to follow the power fit seeing as there is a constant followed by a value with a variable (either k or m) multiplied to a certain power. Units -wise is simple, since the constant is unitless or in radians so all that remains is to show that what's in the parenthesis needs to be s^2:
T= C*[(kg )]^.5 => [(kg*m) ]^.5 => [1 * (s^2)]^.5 = s
[N/m ] [kg*m/(s^2)] [1 1 ]
Seeing this sort of relationship with mass and spring constant we can predict as k=> infinity with a constant mosc T would approach a period of zero at an curve similar to y= (1/x)^.5 seeing as k being in the denominator. However, in that respect, if mosc => infinity with a constant k then T will also approach infinity at an inverse rate compared to the predicted behavior of T vs. k, y= (x)^.5 , seeing as m being in the numerator. According to the graphs below with appropriate curve fit it seems as though our predictions were correct.
| Figure 2A. Our graph of T vs. oscillating mass with appropriate curve fit. |
| Figure 2B. Our T vs. k graph with appropriate powerfit. |
Conclusion:
We found the our source of any uncertainty would lie in the calculations of other groups as well as any inconsistencies in the spring seeing as it swung side to side shortly after the 5 seconds of our trials.


No comments:
Post a Comment